Run "status" will exit the user.py ...

[ckl8964]

At the command line running "status" to view the user status will exit the program and show the error as follow

---

Traceback (most recent call last):
File "", line 1, in
File "/usr/local/lib/python2.7/dist-packages/ethjsonrpc/client.py", line 115, in call
data = self._encode_function(sig, args)
File "/usr/local/lib/python2.7/dist-packages/ethjsonrpc/client.py", line 78, in _encode_function
encoded_params = encode_abi(types, param_values)
File "/usr/local/lib/python2.7/dist-packages/ethereum/abi.py", line 369, in encode_abi
myhead += enc(proctypes[i], args[i])
File "/usr/local/lib/python2.7/dist-packages/ethereum/abi.py", line 344, in enc
return utils.to_string(encode_single(typ, arg))
File "/usr/local/lib/python2.7/dist-packages/ethereum/abi.py", line 242, in encode_single
raise EncodingError("Could not parse address: %r" % arg)
ethereum.abi.EncodingError: Could not parse address: u'0x5e4abd169eb165a21c06dd35f24055baabc716b8'

---

Any idea ?

[thoschm]

Hi, this is probably due to some (not backward compatible) changes in ethjsonrpc, I'll check at the weekend, a quick fix would be to try installing a previous version of it: pip install ethjsonrpc==set.version.here but I have to check.
Thx for reporting!

[tenuki]

This also happens to my.. in my case it worked by removing initial 0x from address...