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Copy pathDAY122 - Mirror Tree
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50 lines (46 loc) · 1.17 KB
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Given a Binary Tree, convert it into its mirror.
Example 1:
Input:
1
/ \
2 3
Output: 3 1 2
Explanation: The tree is
1 (mirror) 1
/ \ => / \
2 3 3 2
The inorder of mirror is 3 1 2
Example 2:
Input:
10
/ \
20 30
/ \
40 60
Output: 30 10 60 20 40
Explanation: The tree is
10 10
/ \ (mirror) / \
20 30 => 30 20
/ \ / \
40 60 60 40
The inroder traversal of mirror is
30 10 60 20 40.
Your Task:
Just complete the function mirror() that takes node as paramter and convert it into its mirror. The printing is done by the driver code only.
Expected Time Complexity: O(N).
Expected Auxiliary Space: O(Height of the Tree).
Constraints:
1 ≤ Number of nodes ≤ 105
1 ≤ Data of a node ≤ 105
********************************************
class Solution:
#Function to convert a binary tree into its mirror tree.
def mirror(self,root):
# Code here
if not root:
return
self.mirror(root.left)
self.mirror(root.right)
root.left, root.right = root.right, root.left
return