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Copy pathLightOj 1033.cpp
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160 lines (133 loc) · 2.54 KB
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// Problem name : 1033 - Generating Palindromes
// Algorithm : DP
// Contest/Practice : Off Line Practice
// Source : LightOj
// Comment :
// Date : 26-Sep-14
#include <vector>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <string>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include<assert.h>
#define pause system("pause")
#define FOR(s,e,inc) for(int i=s;i<=e;i+=inc)
#define mod 1000000007
#define inf 1<<30
#define pb push_back
#define ppb pop_back
#define mp make_pair
#define F first
#define S second
#define sz(x) ((int)x.size())
#define sqr(x) ( (x)* (x) )
#define eps 1e-9
#define gcd(x,y) __gcd(x,y)
#define on(x,w) x=x|(1<<w)
#define check(x,w) (x&(1<<w))==(1<<w)?true:false
#define all(x) (x).begin(),(x).end()
#define pf printf
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
template<class T>
inline T mod_v(T num)
{
if(num>=0)
return num%mod;
else
return (num%mod+mod)%mod;
}
template<class T>
inline void memset1(vector<T>&v,int s,T value)
{
for(int i=0;i<s;i++)
v[i]=value;
}
template<class T>
inline void memset2(vector<vector<T> >&v,int s1,int s2,T value)
{
for(int i=0;i<s1;i++)
for(int j=0;j<s2;j++)
v[i][j]=value;
}
template<class T>
T fast_pow(T n , T p)
{
if(p==0) return 1;
if(p%2)
{
T g=mod_v ( mod_v(n) * mod_v(fast_pow(n,p-1)) );
return g;
}
else
{
T g=fast_pow(n,p/2);
g=mod_v( mod_v(g) * mod_v(g) ) ;
return g;
}
}
template<class T>
inline T modInverse(T n)
{
return fast_pow(n,mod-2);
}
template<class T>
inline void debug(string S1,T S2,string S3)
{
cout<<S1<<S2<<S3;
}
#ifndef ONLINE_JUDGE
# define p(x) cout<<x<<endl;
#else if
# define print(x) 0;
#endif
//.......Code start from here ! .......
int dp[102][102];
string s;
inline void clr()
{
for(int i=0;i<102;i++)
for(int j=0;j<102;j++)
dp[i][j]=-1;
}
int re(int l,int r)
{
if(l>r) return 0;
if(dp[l][r]!=-1) return dp[l][r];
int A=0;
if(s[l]==s[r])
A=re(l+1,r-1);
else
{
A=1+min(re(l+1,r),re(l,r-1));
}
return dp[l][r]=A;
}
int main()
{
int t,tcase=1;
scanf("%d",&t);
while(t--)
{
clr();
cin>>s;
printf("Case %d: %d\n",tcase++,re(0,sz(s)-1));
}
return 0;
}