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86 lines (77 loc) · 2.6 KB
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// Source: https://leetcode.com/problems/implement-queue-using-stacks
// Title: Implement Queue using Stacks
// Difficulty: Easy
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Implement a first in first out (FIFO) queue using only two stacks. The implemented queue should support all the functions of a normal queue (`push`, `peek`, `pop`, and `empty`).
//
// Implement the `MyQueue` class:
//
// - `void push(int x)` Pushes element x to the back of the queue.
// - `int pop()` Removes the element from the front of the queue and returns it.
// - `int peek()` Returns the element at the front of the queue.
// - `boolean empty()` Returns `true` if the queue is empty, `false` otherwise.
//
// **Notes:**
//
// - You must use **only** standard operations of a stack, which means only `push to top`, `peek/pop from top`, `size`, and `is empty` operations are valid.
// - Depending on your language, the stack may not be supported natively. You may simulate a stack using a list or deque (double-ended queue) as long as you use only a stack's standard operations.
//
// **Example 1:**
//
// ```
// Input
//
// ["MyQueue", "push", "push", "peek", "pop", "empty"]
// [[], [1], [2], [], [], []]
// Output
//
// [null, null, null, 1, 1, false]
//
// Explanation
//
// MyQueue myQueue = new MyQueue();
// myQueue.push(1); // queue is: [1]
// myQueue.push(2); // queue is: [1, 2] (leftmost is front of the queue)
// myQueue.peek(); // return 1
// myQueue.pop(); // return 1, queue is [2]
// myQueue.empty(); // return false
// ```
//
// **Constraints:**
//
// - `1 <= x <= 9`
// - At most `100`calls will be made to `push`, `pop`, `peek`, and `empty`.
// - All the calls to `pop` and `peek` are valid.
//
// **Follow-up:** Can you implement the queue such that each operation is **amortized** `O(1)` time complexity? In other words, performing `n` operations will take overall `O(n)` time even if one of those operations may take longer.
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#include <stack>
using namespace std;
class MyQueue {
stack<int> left;
stack<int> right;
public:
MyQueue() {}
void push(int x) { //
left.push(x);
}
int pop() {
int top = peek();
right.pop();
return top;
}
int peek() {
if (right.empty()) {
while (!left.empty()) {
right.push(left.top());
left.pop();
}
}
return right.top();
}
bool empty() { //
return left.empty() && right.empty();
}
};