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CountCompleteTreeNodes.java
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77 lines (62 loc) · 1.79 KB
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/*
Given a complete binary tree, count the number of nodes.
Note:
Definition of a complete binary tree from Wikipedia:
In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h.
Example:
Input:
1
/ \
2 3
/ \ /
4 5 6
Output: 6
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
/*
Time Complexity (logN * logN)
*/
class Solution {
public int countNodes(TreeNode root) {
return count(root);
}
private int count(TreeNode root){
if(root == null){
return 0;
}
//count extreme left depth
int leftDepth = 0;
TreeNode leftNode = root;
while(leftNode != null){
leftDepth++;
leftNode = leftNode.left;
}
//count extreme right depth
int rightDepth = 0;
TreeNode rightNode = root;
while(rightNode != null){
rightDepth++;
rightNode = rightNode.right;
}
//if both the depths are same then its a perfect binary tree, hence the nnumber of nodes = 2 ^ depth - 1;
if(leftDepth == rightDepth){
return (int)Math.pow(2,leftDepth) - 1;
}
//coun the number of nodes in left subtree + right subtree + 1(for current node)
return 1 + count(root.left) + count(root.right);
}
}