IterTools.groupby doesn't group nonconsecutive elements together.

[dafnevk]

When I execute the following code:

my_list = [ ["u",1], ["u",2], ["a",1], ["d", 1], ["a",2],["d",2]]
collect(IterTools.groupby(s->s[1], my_list))

I get as output:

 [["u", 1], ["u", 2]]
 [["a", 1]]
 [["d", 1]]
 [["a", 2]]
 [["d", 2]]

So it seems that the items with key a and d are not properly grouped together.

Environment:
Julia v1.10.9
itertools v1.10.0

[oxinabox]

This is documented.

Group consecutive values that share the same result of applying f.

IterTools.jl/src/IterTools.jl

Line 385 in 5eeba86

Group consecutive values that share the same result of applying `f`.

Same behavour as python's
I know some other language/library does it the way you want, but i can't remember which.
I feel like i did a writeup at some point.
SplitApplyCombine.jl's group is at least on such.

I feel like both are valuable.
and having to call sort before groupby seems unnesc.

Maybe we should just have groupby_consective and groupby_nonconsective, and be really explicit.