search.py

"""
App Store Search - Chocodata App Store Scraper API

Runnable example. It calls the LIVE API and prints the real JSON response.

    pip install requests
    export CHOCODATA_API_KEY="your_key"      # free: 1,000 requests, one-time
    python app_store_scraper_api_codes/search.py

Docs: https://chocodata.com/docs
"""
import json
import os
import sys

import requests

API = "https://api.chocodata.com/api/v1/appstore/search"
KEY = os.environ.get("CHOCODATA_API_KEY")

if not KEY:
    sys.exit("Set CHOCODATA_API_KEY first. Free key (1,000 requests, one-time): https://chocodata.com")


def _check(r) -> None:
    """Map the API's documented errors onto actionable messages instead of a traceback."""
    if r.status_code == 400:
        sys.exit(f"400 invalid_params: {json.dumps(r.json().get('issues', r.text))[:200]}")
    if r.status_code == 401:
        sys.exit("401 INVALID_API_KEY: key missing or not recognised. Get one: https://chocodata.com")
    if r.status_code == 402:
        sys.exit("402 INSUFFICIENT_CREDITS: balance exhausted. Top up or upgrade: https://chocodata.com/pricing")
    if r.status_code == 429:
        sys.exit("429 RATE_LIMITED: over your plan's concurrency. Back off and retry.")
    if r.status_code == 502:
        sys.exit("502 extraction_failed: Apple returned no usable data for this request. "
                 "Retryable. You were not charged.")
    r.raise_for_status()


def search(term: str, country: str = "us", limit: int = 10) -> dict:
    """Search the App Store and return ranked results as structured JSON."""
    params = {"api_key": KEY, "term": term, "country": country, "limit": limit}
    r = requests.get(API, params=params, timeout=90)
    _check(r)
    return r.json()


if __name__ == "__main__":
    data = search("spotify")
    print(json.dumps(data, indent=2, ensure_ascii=False)[:2000])
    print()
    top = data["results"][0]
    print(f"{len(data['results'])} apps | #1: {top['title'][:44]} | "
          f"{top['formatted_price']} | {top['rating']:.2f} stars from {top['reviews_count']:,} ratings")